4/(x+3)-1/(x-3)=4x/x^2-9

Solution for 4/(x+3)-1/(x-3)=4x/x^2-9 equation:

4/(x+3)-1/(x-3)=4x/x^2-9

We move all terms to the left:

4/(x+3)-1/(x-3)-(4x/x^2-9)=0


Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R



Domain of the equation: (x-3)!=0

We move all terms containing x to the left, all other terms to the right

x!=3

x∈R



Domain of the equation: x^2-9)!=0

x∈R


We get rid of parentheses

4/(x+3)-1/(x-3)-4x/x^2+9=0

We calculate fractions


(4*(x-3)*x^2)/((x+3)*(x-3)*x^2)+(-1*(x+3)*x^2)/((x+3)*(x-3)*x^2)+(-4x*(x+3)*(x-3))/((x+3)*(x-3)*x^2)+9=0


We calculate terms in parentheses: +(4*(x-3)*x^2)/((x+3)*(x-3)*x^2), so:

4*(x-3)*x^2)/((x+3)*(x-3)*x^2

We multiply all the terms by the denominator


4*(x-3)*x^2)

We multiply parentheses

-12x^3+4x

We do not support expression: x^3